
Arturo O. answered 11/09/16
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pH = -log10[H3O+]
-pH = log10[H3O+]
10-pH = [H3O+]
[H3O+] = 10-pH = 10-1.7 = 1/101.7 ≅ 0.01995
I think you need more digits than just the nearest hundredth.