Hello, thank you for taking the time to post your question!
To find the equation of the line in slope-intercept form, you can start with the point-slope form, since you have a point and a slope.
The point-slope form is: y−y1=m(x−x1)
Plugging in the given values, with the point (3, 1) and slope -4/7:
y−1=−4/7(x−3)
y−1=−4/7x+12/7
To get the equation into the slope-intercept form (y=mx+b), you need to isolate y. You can do this by adding 1 to both sides.
y=−4/7x+12/7+1
y=−4/7x+12/7+7/7
y=−4/7x+19/7
I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)
