Peter G. answered 10/25/16
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The hypotheses are that the two populations are normally distributed, and that the samples are randomly and independently selected.
Then,
H0: σ12 = σ22
HA: σ12 ≠ σ22
This is a two-tailed test, so we use α/2 = .05
F = 8/12 = 0.667
where D1=40-1=39, and D2=50-1=49
The critical F value from a table is 1.634. Since F ≤ 1.634, we do not reject the null hypothesis . There is not sufficient evidence to support the hypothesis that the two populations have different variances.
For part (b), look up the critical F value corresponding to alpha= .025. However, you can also point out that .025<.05, and since we did not reject at 0.05, we will not reject at 0.025.
I hope that helps.