How do I start?

Question

nt frequency of a circuit may be found by the formula fequals
StartFraction 1 Over 2 pi StartRoot LC EndRoot EndFraction
where f is in cycles per? second, L is in? henrys, and C is in farads. Find the resonant? frequency, to the nearest? thousand, of a circuit if Lequals
7.383 times 10 Superscript negative 4
henrys and Cequals
2.8 times 10 Superscript negative 11
farads.

Answer 1

The natural linear frequency is

 

f_n = [1/(2π)] [1 / √(LC)]

 

Resonance occurs when the frequency of the driving oscillator equals the natural frequency.  Calculate the natural frequency and that is the frequency at which resonance occurs.

 

You are given:

 

L = 7.383 x 10^-4 H

C = 2.8 x 10^-11 F

 

Substitute these values into the equation for f_n and that will give the resonant frequency in Hz, which is cycles per second.  Round off to the third decimal place.