
Andrew M. answered 10/20/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
The average of 5 integers is 60
(a+b+c+d+e)/5 = 60
a+b+c+d+e = 300
The average of 3 of the numbers is 67
(a+b+c)/3 = 67
a+b+c = 201
d+e = 300 - (a+b+c)
d+e = 300-201
d+e = 99
The greatest possible value either of the two other
numbers can be is 99. This would mean the last
2 numbers are 99 and 0