3x^2+28x+16=14 solve the quadratic

Question

Use the quadratic formula to solve the quadratic

Answer 1

3x²+28x+16-14=14-14

3x²+28x+2=0

x={-28±√[(28)²-4x3x2]}/(2x3)

x=2{-14±√[190]}/(2x3)

x={-14±√[190]}/3

Answer 2

3x^2 +28x+16=14  is the same as 3x^2 + 28x+2 = 0

 

a=3  b=28   c=2

 

(-b±√b^2-4ac)/2a

 

(-3±√(28)^2-4(3)(2))/2(3)

 

(-3±√784-24)/6

(-3±√760)/6

 

-3/6 ±(√760)/6

 

you can simplify √760 down a little bit because 760 = 190x4, which means that √760 = √190 x √4

 

now the answer becomes:

-3/6 ± (2/6)√190

 

which simplifies down to:

-1/2 ± (1/3)√190