log (x3)+log (x4) / log(60x) = 5 x=

Question

I can't seem to be able to put the answer on webworkk

Answer 1

log(3x) + log(4x) = log12x^2 divided by log60x

log12x^2/log60x = log(12x^2) to the base 60x = 5x

60x^5x = 12x^2 x=0 might be one solution

Unless you really meant logx^3 + logx^4 = log(x^7) divided by log60x = log(x^7)log60x = log(x^7) to the base 60x = 5x.

60x^5x = x^7 then, x = 0 and also close to x =-2 give or take a little

Although it would help if you revised the problem and make it clearer. Yet trying to figure out the problem is a problem worth trying to solve. call it a problem with an exponent.