Let x = the total amount of 20% solution needed
y = the total amount of 50% solution needed
x + y = 3 (the total volume of the combined solution)
Also, we know that the total concentration of the mixture can be expressed as
x(0.20) + y(0.50) = 3(0.40) [I converted each of the percentages to decimals]
.20x + .50y = 1.2 (Multiply both sides by 100 to clear the decimals)
20x + 50y = 120
Now, solve the first equation for y
x + y = 3 or y = 3 - x
We can plug this into the second equation:
20x + 50(3 - x) = 120
20x + 150 - 50x = 120
-30x + 150 = 120
-30x = -30
x = 1
If x = 1, then y = 3 - x = 3 - 1 = 2
We need 1 L of 20% solution and 2 L of 50% solution