
Jason D. answered 10/12/16
Tutor
4
(1)
Tutoring Math and Science for All Ages
The information we are given look like this when we turn it into an equation.
A = L x W
L = 2W - 5
A = 273 in2
Seeing how L = a function of W we can replace L with the function of W.
273 = (2W - 5) x W
Distribute
273 = 2W2 - 5W
and move everything to one side
0 = 2W2 - 5W - 273
Yes, we use the quadratic formula at this point
(-b ± Sqr(b2 - 4ac))/2a
a = 2 b = -5 c = -273
When we plug these in and calculate the quadratic formula we get
W = 13 and W = -21/2 we can ignore the -21/2 because a width can not be negative
So, our width is 13 inches
Now we take the width and plug it into the L equation we made earlier.
L = 2W - 5
L = 2(13) - 5 = 26 - 5 = 21 inches
L = 21 inches. To verify we will multiply the length and width together to find out if it gives the correct area
A = L x W
21 x 13 = 273in2
so W = 13 and L = 21 inches