Stoiciometry

Question

What volume of 0.100 M barium chloride contains 0.125g of barium chloride?

Answer 1

the molar mass of barium chloride is 208.23 g/mol, meaning that

moles = 0.125 g / 208.23 = 0.0006 mol

from there then you can divide by the given Molarity to find the Volume

Volume = Moles / Molarity

Volume = 0.0006 mol / (0.100 mol/L) = 0.006 L = 6.00 mL

Answer 2

MOLAR Mass of Barium Chloride (BaCl2) is 90 g (56 + 17x2)
The number of Moles of Solute (Barium Chloride) represented by 0.125g
is found by 0.125g x (1 mol/90g) = 0.00139 moles

0.100 M = 0.100 moles solute/Liters of Solution so the Ratio to solve for X is
0.100 moles/L = 0.00139 moles/X (liters)
X = 0.00139/0.100 = 0.0139 Liters
Answer is 0.0139 Liters = 13.9 mL (milliliters)