
Athena W.
asked 10/04/16Problem solving- Complex Numbers and Roots
At a carnival, A new attraction allows contestants to jump off a springboard onto a platform to be launched vertically into the air. The object is to ring a bell located 20 feet overhead. The distance d(t)=16t^2-bt+20, where t is the time in seconds after leaving the platform, and b is the takeoff velocity from the platform.
1. Kate watches some of the contestants. She theorizes that if the platform lanches a contestant with a takeoff velocity of at least 32 ft./s the contestant can ring the bell.
a. Find the zeros for the function using 32 feet per second as the takeoff velocity.
B. Is Kate's theory valid?
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1 Expert Answer

Arturo O. answered 10/04/16
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Experienced Physics Teacher for Physics Tutoring
I suspect the +16 is a typo, unless it is intentional and part of the question. The -16 comes from
d(t) = (1/2)at2 + v0t + d0
a = -g = -32 ft/s2
v0 = initial vertical velocity imparted by the platform, v0 positive up
d0 = height of platform (assume it is zero?)
Then
d(t) = -16t2 + v0t
Assume v0 = 32 ft/s, and you want to reach a height of 20 ft. Is there a time t when this is realized?
20 = -16t2 + 32t
-16t2 + 32t - 20 = 0
Multiply both sides by -1 and get
16t2 - 32t + 20 = 0
Divide by 4 to simplify a little.
4t2 - 8t + 5 = 0
t = [8 ± √(64 - 4*4*5)] / 8
Note you get a complex number, so a launch speed of 32 ft/s will not get you up to 20 ft.
d(t) = (1/2)at2 + v0t + d0
a = -g = -32 ft/s2
v0 = initial vertical velocity imparted by the platform, v0 positive up
d0 = height of platform (assume it is zero?)
Then
d(t) = -16t2 + v0t
Assume v0 = 32 ft/s, and you want to reach a height of 20 ft. Is there a time t when this is realized?
20 = -16t2 + 32t
-16t2 + 32t - 20 = 0
Multiply both sides by -1 and get
16t2 - 32t + 20 = 0
Divide by 4 to simplify a little.
4t2 - 8t + 5 = 0
t = [8 ± √(64 - 4*4*5)] / 8
Note you get a complex number, so a launch speed of 32 ft/s will not get you up to 20 ft.
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Arturo O.
10/04/16