N/-2-1=9 ????

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(n/-2) - 1 = 9

we'd cross the -1 over the equality sign making it +1

so we'd have,

(n/-2) = 9 + 1

which gives;

(n/-2) = 10

open the brackets

n/-2 = 10

to solve for n, we cross multiply both sides remembering that 10 is the same as 10/1

so we'd have;

n * 1 = -2 * 10

giving

n = -20

Shelly J. | Excellent Maths Tutoring for academic successExcellent Maths Tutoring for academic su...

Hi Jeannette,

(n/-2)-1=9

add +1 to both the sides

(n/-2)-1+1=9+1

(n/-2)=10

Multiply (-2) on both the sides to solve for n

(n/-2)(-2)=10(-2)

n=-20

Hi Jeannette;

n/-2 -1=9 ?????

I think this is...

(n/-2)-1=9...Please correct me if I am wrong.

Let's multiply both sides by -2...

-2[(n/-2)-1]=-9(2)

A negative number multiplied by a negative number results in a positive number...

n+2=-18

Let's subtract 2 from both sides...

-2+n+2=-18-2

Let's check our results...

(n/-2)-1=9

(-20/-2)-1=9

A negative number divided by a negative number results in a positive number...

10-1=9

9=9

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