We can pull out the 3, leaving a fraction.

3K - 7 → 3(K - 7/3)

I dont understand how to distributive property to rewrite the equation n than solve for each variable ?

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Hey Jeannette, to distribute something to is when you have a coefficient in front of something in parenthesis and you need to multiply all of those numbers in the parenthesis by the coefficient.

Example:

3(X + 2Y) → 3X + 6Y

You can also do this in reverse, pulling out the common factor.

6X + 3Y → 3(2X + Y)

With the problem we have here there are two ways we can do it.

We can pull out the 3, leaving a fraction.

3K - 7 → 3(K - 7/3)

We can pull out the 3, leaving a fraction.

3K - 7 → 3(K - 7/3)

Or, to keep it at whole numbers we can subtract 32 from each side, and then factor

3K - 7 = 32 → 3K - 39 = 0 → 3(K - 13) = 0

If you are trying to solve the equation, then you just need to get K by itself on one side. This is similar to what we did before. Add 7 to both sides, and then divide each side by 3.

3K - 7 = 32 → 3K = 39 → K = 13

3k-7=32

Add 7 to both sides:

3k = 39

Divide by 3 both sides:

k = 13

The distributive property wasn't used for this solution.

Hi Jeannette;

3k-7=32

We want...

3(k-__)

Obviously, the number 7 is not good to use for the blank position. So let's move the 32 from the right side to the left...

3k-7-32=0

3k-39=0

3(k-13)=0

This distributes as...

(3)(k)=3k

(3)(13)=39

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