f(x) = √(3x-12) is a one-to-one function with domain [4,∞) and range [0,∞).
Since f(x) is one-to-one, f(x) has an inverse function with domain [0,∞) and range [4,∞).
Find f-1(x): y = √(3x-12) y2= 3x-12
y2+12 = 3x
x = (y2+12)/3
Switch x and y to get y = (x2+12)/3
f-1(x) = (x2+12)/3, where x≥0
x