
Leonard S. answered 09/29/16
Tutor
New to Wyzant
Leonard S. Math and Accounting Tutor
For the first 2 pairs just substitute for x and solve for y
y = (2/5)*0 - 2
y = 0 - 2
y = -2
(0, -2)
y = (2/5)*5 - 2
y = 2 - 2
y = 0
(5,0)
For the last 2, substitute for y and solve for x
1 = (2/5)x - 2 add 2 to both sides to isolate x
3 = (2/5)x Multiply both sides by (5/2)
15/2 = x
(15/2, 1)
-3 = (2/5)x - 2 same procedure as before
-1 = (2/5)x
-5/2 = x
(-5/2.-3)