Alex C.
asked • 09/25/16Limits at infinity with a radical
lim x--> -infty ( 4x-3)/(25x^2+4x)
Im not sure if this is a legititamte way of solving but heres how I attempted:
I took the highest power at the bottom and top and just left it like that so (4x/sqrt25x^2) then simplified to (4x/5x) and final answer -4/5 . I put the - last because its -infty
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1 Expert Answer
Arturo O. answered • 09/25/16
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Alex, have you worked with L'Hopital's rule in your class? By that rule,
limit x → -∞ of (4x - 3) / (25x2 + 4x) = limit x → -∞ of 4/(50x + 4) = 0
Arturo O.
By the way, I worked the problem as originally stated, which had no radical. Alex, did you intend to put a radical in the problem? Note Michael's question.
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09/25/16
Arturo O.
For the restated problem, the method is the same: apply L'Hopital's rule. Sometimes, application of the rule produces a second indeterminate form. Then apply the rule to that second form, and if necessary, keep on applying it to resulting forms until you get a determinate form.
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09/25/16
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Michael J.
09/25/16