Phil P.

asked • 09/11/16

Algebra laws??

Why does the calculation change if you know / don't know the value of the symbols?

for example  3a(2d+bc)-4c

I get 6ad+3abc-4c.

BUT....If the values are given a=2 b=3 c=4 d=6

With these values I get a final answer of 44 using the above calculation which apparently is correct if you DONT know the values, however this is wrong since now we are given the values. The actual answer is:

128.

I don't understand why you multiply each part of the inside of the bracket with the outside of the bracket when you don't know any values which by my understanding, goes against BODMAS.
However, if you know the values, you calculate the problem using BODMAS.

But each way is correct if you don't know the value. This has confused me so that I now don't know when to do each type of multiplication.

Please help me

3 Answers By Expert Tutors

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Kendra F. answered • 09/11/16

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Ira S. answered • 09/11/16

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Phil P.

Thank you for your quick response. What I am having trouble with is the way the problem is calculated if you know or don't know the value of the symbols.
 
as per the original post: if the values of the symbols are not given, the correct answer would be 6ad+3abc-4c.
why is the outcome different if you don't know the value of the symbols?
 
i can't understand it. Thank you again.
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09/11/16

Neal D.

6ad + 3abc -4c
 
= 6(2)(6) + 3(2)(3)(4) - 4(4)
 
= 72 + 72 -16
 
= 128
 
replacing the variables with numbers won't change the value of the outcome
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09/11/16

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