
Andrew H.
asked 09/11/16Having trouble solving this question.
An object is dropped from 34 feet below the tip of the pinnacle atop a 934-ft tall building. The height h of the object after t seconds is given by the equation h=-16^2 + 900. Find how many seconds pass before the object reaches the ground
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1 Expert Answer

Victoria V. answered 09/11/16
Tutor
5.0
(402)
20+ years teaching Algebra 2 subjects & beyond.
If the equation of the height is given by
h=-16t2+900
You would replace "h" with the height when it reaches the ground, which is 0.
0 = -16 t2 +900
Subtract 900 from both sides.
-900 = -16 t2
Divide both sides by -16
56.25 = t2
Take the square root of both sides to find t.
7.5 = t
Final answer: It took 7.5 seconds to reach the ground.
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Arturo O.
09/11/16