How to find the perimeter of an Irregular Hexagon with coordinates?

Question

If you have the points (-2,4) (0,4) (2,0) (2,-2) (0,2) (-2,2), how can you find the perimeter? I've been on this for hours now and nothing on the internet seems to understand it.

Answer 1

Certainly the formula can be used. Yet should you plot the points (or look at the coordinates) you can see:

AB = 2

BC = 2

CD = 2

DE = 4

EF (this one needs the formula)

FA = 4

Answer 2

David,

 

You need to calculate the distance between each adjacent pair of coordinates.

 

The distance formula is

d = √[(x₂-x₁)² + (y₂-y₁)²]

 

 

This is what I have for your points in order

A (-2,4)

B  (0,4)

C  (0,2)

D  (2,0)

E  (2,-2)

F  (-2,2)

 

So calculate the distance using the given formula for 

 

AB

BC

CD

DE

DF

FA 

and sum

 

That will be your perimeter.