Order of Operations

Question

3 x²+5xy+y²  When x=2 y=5

Answer 1

3x² + 5xy + y² = ?

 

x=2

 

y=5

 

Substitute x and y into the given equation and get 

 

3(2²) + 5(2*5) + 5² = 3(4) + 5(10) + 25 = 87

Answer 2

3x² + 5xy + y²

 

When x=2 and y=5:

 

3(5²) + 5(2)(5) + 5²

 

Exponents first:

 

3(25) + 5(2)(5) + 25

 

Multiplications next, left to right:

 

75 + 50 + 25

 

Additions last:

 

150