Andrew M. answered 09/09/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
16x5x3y5
-----------
28x13y-2
First look at the constants (coefficients).. plain numbers
16/28 can be reduced by a factor of 4
16/28 = 4/7
Look at the x varaibles:
x5x3/x13 = x8/x13
Both can be reduced by a factor of. x8
x8/x13 = x8/x8x5 = 1/x5
Look at the y variables:
y5/y-2
Note: x-n= 1/xn
and 1/x-n = xn
Thus; 1/y-2 = y2
So: y5/y-2 = y5y2 = y7
putting this back together:
16x5x3y5 4y7
----------- = --------
28x13y-2. 7x5
Noah J.
09/09/16