Inactive Tutor answered 09/05/16
Tutor
New to Wyzant
K= 1/2 mv2
v2 =2K/m
v= √(2K/m)
A= π r2 C= 2π r r= C/2π
Thus, A = π x (C/2π)2
= π x C2/4π2
= C2/4π
Thus C2 = 4Aπ C =2√(Aπ)
Inactive Tutor
Hi Alex, sorry i missed that.
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09/05/16
Inactive Tutor
09/05/16