
Amy S. answered 08/28/16
Tutor
New to Wyzant
NC State Grad Tutoring in Math and Science
Let x=stock "A" and y= stock "B"
together they total 24500 stocks so:
x+y=24500
The cost of each stock is represented by 100(x) and 25(y) respectively
And the total cost of stocks sold is 800000, so:
100x+25y=800000
Rearrange the first equation and substitute it into the second equation to find the number of one of the stocks.
x=24500-y
100(24500-y)+25y=800000 Solve for y
2450000-100y+25y=800000
2450000-75y=800000
-75y=-1650000
y=22000
Remember y represents the number of stock "B" sold so if you know y you can put it into the original first equation and find x, or the number of stock "A" sold, so:
x+22000=24500
x=2500
The shares of one of the stocks sold is 22000 and the shares of the other stock sold is 2500
Put those numbers back into the equations to check your work