Perform the indicated operation - Show Work

Question

g(n) = n - 1

f(n) = n^3 - 3n

Find g(n) + f(n)

Answer 1

g(n) = n - 1

f(n) = n³ - 3n

 

g(n) + f(n) = n - 1 + n³ - 3n

                 = n³ -2n - 1

Answer 2

g(n) = n - 1

 

f(n) = n³ -3n

 

g(n) + f(n) = n - 1 + n³ - 3n

 

                 = n³ - 2n - 1