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Parviz F. | Mathematics professor at Community CollegesMathematics professor at Community Colle...

Need to choose 2 numbers a, b in such a way that a+ b = -7 ab = 12* 6 =72

72= 36 . 2 = 18 . 4 = 9 . 8 = 3 . 24=12 .6

Factoring by completing the square:

6 t^2 - 7t + 12 =

6 ( t ^2 - 7/6 t +12/6) =

6[ ( t^2 - 2( 7/ 12) + 49/ 144 - 49/144 + 12/6)]

6 [( t - 7/12) ^2 +239/144) =

6 [( t- 7/12 + i(√239/12 ) ( t - 7/12 - i(√239/12 ) ]

ac = 6 = 1*2*3 = 1*6 = 2*3,

bd = 12 = 1*2*2*3 = 1*12 = 2*6 = 3*4,

ad+bc = -7

a . . . c . . . b . . . d . . . ad+bc

6 . . . 1 . . . -1 . . -12 . -72 -1 = -73

6 . . . 1 . . . -12 . . -1 . -6 -12 = -18

6 . . . 1 . . . -2 . . -6 . . -36 -2 = -38

6 . . . 1 . . . -6 . . -2 . . -12 -6 = -18

6 . . . 1 . . . -3 . . -4 . . -24 -3 = -27

6 . . . 1 . . . -4 . . -3 . . -18 -4 = -22

2 . . . 3 . . . -1 . . -12 . -24 -3 = -27

2 . . . 3 . . . -12 . . -1 . -2 -36 = -38

2 . . . 3 . . . -2 . . -6 . . -12 -6 = -18

2 . . . 3 . . . -6 . . -2 . . -4 -18 = -22

2 . . . 3 . . . -3 . . -4 . . -8 -9 = -17

2 . . . 3 . . . -4 . . -3 . . -6 -12 = -18

Having exhausted all the possible integer factors we can say the equation cannot be factored over the integers.

Let's use Vertex Form of:

f(t) = 6t^2 - 7t + 12 = 6(t - h)^2 + k

h = - b /(2a) = - -7/(2*6) = 7/12

k = f(h) = f(7/12) = ((6)(7/12) - 7)(7/12) + 12

= (42/12 - 84/12)(7/12) + 12

= (-42/12)(7/12) + 12

= -294/144 + 1728/144 = 1434/144 = 717/72 = 239/24

f(t) = 6(t - 7/12)^2 + 239/24 = 0

6(t - 7/12)^2 = -239/24

(t - 7/12)^2 = -239/144

t - 7/12 = +- i*sqrt(239)/12

t = 7/12 +- i*sqrt(239)/12

So in factored form:

f(t) = (t-(7/12 + i*sqrt(239)/12))(t-(7/12 - i*sqrt(239)/12))

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