
Somayeh V. answered 08/08/16
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PhD in Mathematics, Experienced Tutor and Teacher
Suppose that A has n elements and B has m elements. The number of proper subsets of A is 2^n-1 and the number of proper subsets of B is 2^m-1. So we have (2^n-1)-(2^m-1)=496 which gives 2^n-2^m=496. We can write this as 2^m(2^(n-m)-1)=496. Note that 2^m is a power of 2, 2^(n-m)-1 is an odd number, and 496=(2^4)(31). So we must have m=4 and 2^(n-m)-1=31 which gives 2^(n-m)=32=2^5, and so n-m=5. Hence n=9 and the number of subsets of A is 2^9.