Help with dividing e^-x

Question

How does the equation 

ye^-x = -16e^-x +C 

 

go to 

 

y= -16+Ce^-x

 

how does the c get multiplied by the e^-x rather than divided?

Answer 1

It doesn't.

 

The correct answer is y = -16 + Ce^x, assuming ye^-x = -16e^-x +C is correct.

The final equation has each term of the original equation divided by e^-x and 1/e^-x = e^x