David F. answered 08/01/16
Tutor
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(2)
Math Wiz from MIT
Yes, take the derivative and set it equal to zero.
d/dx [cos^2(6x)] = -12cos(6x)sin(6x)
Set it equal to zero
cos(6x)sin(6x) = 0
cos(x) and sin(x) both have period of 2pi
cos(6x) and sin(6x) both have period of pi/3 which is 2pi/6
Over that period, sin(6x) crosses zero twice so the period of sin(6x) = 0 is pi/6
and period of cos(6x) = 0 is pi/6.
cos(6x) = 0 when x = pi/12, p/12 + pi/6, etc. to 7pi/12
sin(6x) = 0 when x = pi/6, pi/6 + pi/6, etc. to 2pi/3 (2.094)
the intervals are:
(pi/12, pi/6), (3pi/12, pi/3), (5pi/12, pi/2), (7pi/12, 2pi/3)
You can confirm that the slope is increasing by picking a value in each interval
and checking that the slope is positive.
The interval (pi/12, pi/6) is in the 2nd quadrant where cos is - and sin is +
so the slope is + (remember the negative sign in the 1st derivative).
The interval (3pi/12, pi/3) is in the 4th quadrant where cos is + and sin is -
so the slope is +
so the slope is +
Parmanand P.
08/01/16