
Norbert W. answered 07/20/16
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4.4
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Math and Computer Language Tutor
A. Let L = length of the rectangle = 3.7 cm and W = 8.4 cm width of the rectangle.
Area: A = L * W = 31.08 cm2
Perimeter: P = 2*(L + W) = 24.2 cm
B. Let r = 5 m radius of circle.
Area: A = π * r2 = 25π ≈ 78.54 m2
Circumference: C = 2πr = 10π = 31.42 m
Circumference is the perimeter for a circle.
C. Let the sides be s1 = 23 mm and s2 = 17 mm and h1 = 15 mm
h1 is the altitude to the longer side, which is s1
Area: A = s1*h1 = 345 mm2
Perimeter: P = 2*(s1 + s2) = 80 mm
D. Let a = 8 m and b = 5 m
The third side c (hypotenuse) can be found using Pythagoras' Theorem:
c2 = a2 + b2 = 89 => c =√89
Area: A = 1/2 * a * b = 20 m2
Perimeter: P = a + b + c = 13 + √89 ≈ 22.43 m