Set your width as "x" and the length as "x+6".
Since there are two sides to each rectangle, the equation will be x+x+x+6+x+6 or 4x+12=48. You should be able to find the width as "x" and the length as "x+6" (ans: 9in and 15in, respectively). The width is 9 inches.
Once you know the side lengths, the area is an easy calculation of L x W. (ans: 135in2)
Since there are two sides to each rectangle, the equation will be x+x+x+6+x+6 or 4x+12=48. You should be able to find the width as "x" and the length as "x+6" (ans: 9in and 15in, respectively). The width is 9 inches.
Once you know the side lengths, the area is an easy calculation of L x W. (ans: 135in2)
I hope this helps!