standard deviation

Question

Nationwide it has been shown that the average height of American adult men is approximately 69.7 inches and a standard deviation of 2.7 inches. Assuming that the heights are normally distributed and using the Standard Scores and Percentiles table from 6C in your textbook, give the standard z-score and the approximate percentile for an American adult man who measures 5 foot 10 inches (70 inches) in height.

Answer 1

z = (X - μ) / σ

z = (70 - 69.7) / 2.7

z = 0.3 / 2.7

z ≈ 0.1111

 

54.38% according to my table.