
Mark M. answered 07/05/16
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
|x + 7| ≤ 15
An absolute value inequality must be solved twice. Once assuming the argument is positive and once assuming the argument is negative.
I. If x + 7 ≥ 0
|x + 7| ≤ 15
x + 7 ≤ 15
x ≤ 8
II. If x + 7 < 0
|x + 7| ≤ 15
-(x + 7) ≤ 15
x + 7 ≥ -15
x ≥ -22
-22 ≤ x ≤ 8