Jonathan Y.

asked • 06/25/16

Algebra/NT Question

Prove that a^2+b^2+c^2+d^2 = abc+abd+acd+bcd has a solution in integers for which a, b, c, d are greater than N for all real values of N.
 
Can someone help me in this question? I tried Vieta Jumping, but can't seem to get an answer.

Mark M.

1) This is hardly an "Introductory Algebra Question."
2) Vieta Jumping is method in the area of Number Theory.
3) "greater than N for values of N" is nonsensical.
Report

06/25/16

Jonathan Y.

Sorry, I meant for all values of N
Report

06/25/16

Jonathan Y.

And N is a real number
Report

06/25/16

Mark M.

How can a, b, c, and d be greater than all N?
Report

06/25/16

1 Expert Answer

By:

Alan G. answered • 06/26/16

Tutor
5 (4)

Successful at helping students improve in math!

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.