What equation describes the line passing through the points (3,0)and(-5,-8)

Question

Algebra 1 is this 

Answer 1

Hi Jordan,

Recall that the general equation for a line is y=mx+b where m is the slope and b is the y-intercept.

First, let's find the slope by finding (y₂-y₁)/(x₂-x₁):

(-8-0)/(-5-3)

-8/-8

1

 

Now we know the equation is y=1x+b, or y=x+b.

By plugging in one of the two points we know is on the line, we can solve for b.

0=3+b

b=-3

 

So the equation is:

y=x-3