
James B. answered 06/08/16
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Let x = number of standard downloads
Let y = number of high quality downloads
x + y = 1090
2.2x + 4.2y = 2998
Solving for x in the first equation,
x + y = 1090
x = 1090 - y
we can now substitute into the second equation
2.2(1090 - y) + 4.2y = 2998
2398 - 2.2y + 4.2y = 2998
2y = 2998 - 2398
2y = 600
y = 300
There were 300 high-quality downloads