The perimeter of a rectangle lot is 156 meters. The length is twice the width. What is the equation that describes this situation.

Question

it's hard for me to process

Answer 1

P = 2(L+W) = 156 m

 

L = 2W

 

So P = 2(2W + W) = 2(3W) = 6W = 156 m

 

W = 156 m / 6 = 26 m

 

L = 2W = 2(26 m) = 52 m

 

We have a rectangle of length 52 m and width 26 m. 

Answer 2

Hi Carson, the equation is: P = 2 * L + 2 * W. Since the length is equal to twice the width, this gives L = 2 * W.

 

Substitute for L in the given equation:

 

P = 2 * ( 2 * W) + 2 * W

 

P = 6 * W

 

the perimeter of the rectangle is 156 meters. Substitute for P:

 

156 = 6 * W

 

Now all you have to do is find the value of W and then substitute for W in: L = 2 * W, to find L.

 

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