
Mark M. answered 06/05/16
Tutor
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Mathematics Teacher - NCLB Highly Qualified
an = a1 + (n - 1)d
399 = 3 + (n - 1)4
396 = 4n - 4
400 = 4n
100 = n
Sn = (n/2)(a1 + an)
S100 = (100/2)(3 + 399)
S100 = (50)(402)
S100 = 20100
Mark M.
06/05/16