
James B. answered 05/30/16
Tutor
5.0
(3,069)
GED Math; Prealgebra; Algebra
Let x = speed wind
Let t = time
Rate * time = distance ... the time is the same (according to problem specifications) ... the distance is provided
With the wind ... rate = 250 + x
Against the wind ... rate = 250 - x
We construct our equations ...
WITH THE WIND:
rate * time = distance
(250 + x) * t = 300
AGAINST THE WIND:
rate * time = distance
(250 - x) * t = 200
We now have 2 equations ... we can solve both of then for the time. That gives us these 2 equations
t = 300/(250 + x)
t = 200/(250 - x)
Using substitution, we end up with this 1 variable equation involving x:
300/(250 + x) = 200(250 -x)
Solving for x ... x = 50 ... the speed of the wind