what's the average of the 8 new numbers?

Question

The average of 8 numbers is 6.5. If each of the numbers is decreased by 3, what's the average of the 8 new numbers?

Answer 1

If the original total of the 8 numbers was x then

x/8 = 6.5

x = 6.5(8)

x = 52

 

From this total we will subtract three 8 times or subtract 24

Our new average is:

(x-24)/8 =

(52-24)/8 = 28/8 = 3.5

Answer 2

you actually can just subtract by 3 in this case because the "3" is being taken away from each number

that makes the New Average here

6.5 - 3 = 3.5

Answer 3

(a+b+c+d+e+f+g+h )/ (8) = 6.5

 

(a-3)+(b-3) + (c-3) + (d-3) + (e-3) + (f-3) + (g-3) + (h-3) / 8 = [(a+b+c+d+e+f+g+h) -24] / (8)

 

(a+b+c+d+e+f+g+h)/8 - 3 = 6.5 - 3