What is the axis of symmetry, domain and range for f(x)=(x-3)^2+1

Question

What is the axis symmetry, domain, and range of f(x)=(x-3)^2+1

Answer 1

f(x)=(x-3)²+1

 

Compare the given definition of f(x) to y = a(x-h)² + k which is the form that contains h & k (coordinates of vertex).

 

So v(3,1) and this means that axis of symmetry EQUATION is x = 3 (goes through vertex) and range is y ≥ k (because vertex is lowest point on upward-opening parabola).

 

Range: [1,infinity)