
Arnold F. answered 05/04/16
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College Professor & Expert Tutor In Statistics and Calculus
If the dimensions of the box are x,y,z the volume is V=xyz.
The surface area will be A=2(xy + yz +xz)
A can then be written as:
A = 2(xy + y[100/xy] + x[100/xy])
= 2(xy + 100/x + 100/y)
calculate ∂A/∂x and ∂A/∂y and set each equal to 0.
Using those two equations solve for x and y (they won't be whole number so adjust your answer.)
Then solve for z to that will give xyz=100.
My guess is the dimensions to minimize the area of each box should be 4,5,5.
Any questions?