(1-1/x3)÷(1-1/x2) = [(x3-1)/x3]÷[(x2-1)/x2]
= [(x3-1)/x3]·[x2/(x2-1)]
= [(x-1)(x2+x+1)/x3]·[x2/((x-1)(x+1))]
= (x2+x+1)/[x(x+1)]
Johnathan E.
asked 04/28/16
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