
Robert D. answered 04/27/16
Tutor
5
(10)
College Physics Grad with Extensive Tutoring Experience
A)
Let x be the amount of time spent moving with the "toss it" company.
Let y be the amount of time spent moving with the "crash boom" company.
Johan believes the move should take 6 hrs regardless of which company he chooses, so x and y both equal 6. Those are two trivial equations.
x = 6
y = 6
Now the total cost of moving with the "toss it" company is $120 plus $25 for every hour spent moving, which is expressed as
$120 + $25x,
and since Johan is only willing to spend 6 hrs to move with either company, x = 6. Therefore, the total cost of moving with "toss it" is
$120 + $25(6) = $120 + $150 = $270.
Now the total cost of moving with "crash boom" is $50 plus $40 for every hour spent moving, which is expressed as
$50 + $40y.
Again, the time spent moving with either company is the same, so y = 6. Therefore, the total cost of moving with "crash boom" is
$50 + $40(6) = $50 + $240 = $290.
B)
1st hr with "toss it" = $120 + $25(1) = $145.
1st hr with "crash boom" = $50 + $40(1) = $90
2nd hr with "toss it" = $120 + $25(2) = $170.
2nd hr with "crash boom" = $50 + $40(2) = $130
3rd hr with "toss it" = $120 + $25(3) = $195.
3rd hr with "crash boom" = $50 + $40(3) = $170
3rd hr with "crash boom" = $50 + $40(3) = $170
4th hr with "toss it" = $120 + $25(4) = $220
4th hr with "crash boom" = $50 + $40(4) = $210
5th hr with "toss it" = $120 + $25(5) = $245
5th hr with "crash boom" = $50 + $40(5) = $250
It is cheaper to hire "toss it" after the 5th hour.
C)
Johan should hire the "toss it" company because it costs $270, as opposed to "crash boom" which costs $290.