
Sue H. answered 05/15/16
Tutor
New to Wyzant
Experienced Math Tutor
Hi Brayan,
Remember absolute value problems have two possibilities that you have to solve separately:
Once you get an equation arranged so only the absolute value part is on one side: |inside| = magnitude, then rewrite it without the absolute value signs:
inside = +magnitude OR inside = –magnitude
For |x+6|=2x-1, separate the 2 possibilities:
x+6 = +(2x-1) OR x+6 = –(2x-1)
Then separately solve for x in each equation.
...
<<Algebraic simplifications happen here.>>
…
7 = x OR 3x = -5
So, possible solutions:
x = 7 OR x = -5/3
First. Note the two possible solutions for x are NOT ± of each other. The +6 as part of the inside makes the solutions not opposites.
Second. Note that if you substitute the second possible solution (-5/3) into the original equation, you get a negative answer on the right hand side and the left hand side, because of the absolute value signs, MUST be positive. So -5/3 is not a solution. 7 is the only solution.
Sue
Remember absolute value problems have two possibilities that you have to solve separately:
Once you get an equation arranged so only the absolute value part is on one side: |inside| = magnitude, then rewrite it without the absolute value signs:
inside = +magnitude OR inside = –magnitude
For |x+6|=2x-1, separate the 2 possibilities:
x+6 = +(2x-1) OR x+6 = –(2x-1)
Then separately solve for x in each equation.
...
<<Algebraic simplifications happen here.>>
…
7 = x OR 3x = -5
So, possible solutions:
x = 7 OR x = -5/3
First. Note the two possible solutions for x are NOT ± of each other. The +6 as part of the inside makes the solutions not opposites.
Second. Note that if you substitute the second possible solution (-5/3) into the original equation, you get a negative answer on the right hand side and the left hand side, because of the absolute value signs, MUST be positive. So -5/3 is not a solution. 7 is the only solution.
Sue