
Norbert W. answered 07/06/16
Tutor
4.4
(5)
Math and Computer Language Tutor
lim (x->0) sin(6x)/sin(8x) = lim (x->0) (6 cos(6x))/(8 cos(8x)) (Using L'Hopitals Rule)
= (6 * 1)(8 * 1) = 6/8 = 3/4
lim (x-0) sin(x)/x^(1/2) = lim (x->0) cos(x)/(1/2 * x^(-1/2) (Using L'Hopitals Rule)
= lim (x->0) 2 *x^(1/2) * cos(x) = 2 * 0 * 1 = 0
lim (x * sin(x)) /(1 - cos(x)) = lim (x->0) (sin(x) + x * cos(x))/sin(x) (Using L'Hopitals Rule)
= lim (x->0) (cos(X) + cos(x) - x *sin(x))/cos(x) (Using L'Hopitals Rule)
= lim (x->0) (2 - x*sin(x)/cox(x)) = 2