Hi Joanna,
Let x represent the length of the original square and x-2 represent the length of a side of the reduced square. Therefore the area of the original square is x2 and the area of the reduced square is (x-2)2. Since the area was decreased by 36 in.2, then
x2 - (x-2)2 = 36
x2 - (x2 - 4x +4) = 36
x2 - x2 +4x - 4 = 36
4x - 4 = 36
4x = 40
x = 10 Therefore, the length of the original square is 10 in.