4x

^{2}+25y^{2}=1^{ }-
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4x^{2}+25y^{2}=1^{
}

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Write in standard form as x^{2}/(1/4)+y^{2}/(1/25)=1

The major axis is of length 2√1/4=2×1/2=1

The minor axis is of length 2√1/25=2×1/5=2/5

The center is at (0,0)

The focal length is determined by c=√(1/4-1/25)=√((25-4)/100)=(√21)/10

It crosses the x-axis at x^{2}=1/4 or at x=±1/2

The foci are at x=±(√21)/10,y=0

The eccentricity is c/a=((√21)/10)/(1/2)=(√21)/5

What else do you mean by solve?