Roman C. answered 04/03/16
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Masters of Education Graduate with Mathematics Expertise
We start with a z-score z* such that P(|z|< z*) = 0.85
So P(z < -z*) = (1 - 0.85)/2 = 0.075, which happens at z* = 1.43953...
Thus we want the standard error to be (0.15/1.43953...) = 0.1042... kWh
σ/√n = SE ⇒ n = (σ/SE)2 = (2.5/0.1042...)2 = (23.992...)2 = 575.6...
We must round up. So we need a sample size of at least 576.
Kayla G.
where did you get 1.4395304/15/20