Alan G. answered 03/30/16
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Since this limit does not have the indeterminate form 0/0 or ∞/∞, you will need to do some rewriting to find it.
Notice that x tan (1/x) tends to ∞ · 0, so you must alter the form of the function to match one of the two fractional indeterminate forms. The best way to do this is to put the factor x in the denominator as 1/x:
limx→∞ x tan (1/x) = limx→∞ (tan 1/x) / (1/x).
At this point it is useful to replace 1/x by t, so that as x→∞, t→0+. The problem then becomes that of
limt→0+ (tan t)/t = limt→0+ (sec2 t)/1 = sec2 0 = 1 (the last step because sec2 t is continuous for t near 0).