
Scott W. answered 03/29/16
Tutor
4
(1)
Understanding Math from any perspective
P0 is the initial population, or population at time=0, P0 = 588,450
you need to solve for k. k=growth constant. in other words, every whole number for k, is an increase of the number e.
e1 approx. = 2.718, e2 approx. = 7.389, and so on.
We need to equate this and the annual growth rate of .032 P.
k=ln(1+r/100)/period. in your case the period is 1 year and r = 3.2
k = ln(1+3.2/100)/1=0.0315
therefore, P(t) = P0 e0.0315 t
and P(16) = 588450 e0.0315*16 = 974078.56, an increase of 385628 people.
taking the derivative,
dp/dt = 588450*0.0315*e0.0315 t = 18536.175 e0.0315 t
evaluated at t=16,
18536.175 e0.0315*16 = 30683.47, the increased number of people in the 16th year.